Hi, I am trying to understand the disk layout for a NCR Deskmate CP/M system for a friend. The image file is 320k, 40 track, 2 head, 8 sector per track, 512 byte sectors. It appears the image file is laid out as side 0 then side 1 instead of the normal layout of Track 0, head 0 followed by Track 0, head 1. If I examine the image as used by the system, the directory starts at 6000h. If I sort the image file in track order so the side 0 is first followed by side 1, then the Directory starts at 3000h. I’m using STAT.COM as a test case for extraction since I have a known good copy to compare the extracted version. The directory lists Allocation blocks as 4d, 4e, and 4f. STAT.COM is 6,144 bytes using 8k on the disk on my PC. Three allocation blocks would support a 2k ALB size. Using 0x4D, STAT.COM should start at offset 29800h (77 * 2048 + 12288 = 169984 (29800h), ALB * ALB Size + Directory Start). No so lucky. I searched the binary image for the first few bytes in STAT.COM and found it at offset 1E800. Does anyone have a good understanding of the disk organization? Thanks, Darrell CPM_2-2-03_DISTRIBUTION_1.IMG CP/M DISK IMAGE === ======== === ==== ========= Usr FILE EXT SIZE FLAGS === ======== === ==== ========= 0 ASM COM 8.0 0 ASSIGN COM 2.0 0 BIOS SYS 5.0 R/O S 0 CONFIGUR COM 14.0 0 DDT COM 5.0 0 DUP COM 5.0 0 ED COM 7.0 0 FORMAT COM 6.0 0 LOAD COM 2.0 0 MOVCPM17 COM 11.0 0 PIP COM 8.0 0 STAT COM 6.0 0 SUBMIT COM 2.0 0 SYSGEN COM 2.0 0 XSUB COM 1.0 === ======== === ==== ========= Files 15, Total 84 K, Free 16 K, Disk Size 100 k Total Files 15, Total File Size 84 K